X^2+8x-284=0

Solution for X^2+8x-284=0 equation:

X^2+8X-284=0

a = 1; b = 8; c = -284;
Δ = b2-4ac
Δ = 82-4·1·(-284)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-20\sqrt{3}}{2*1}=\frac{-8-20\sqrt{3}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+20\sqrt{3}}{2*1}=\frac{-8+20\sqrt{3}}{2}
$